F(x)=x/1+x^2

Solution for F(x)=x/1+x^2 equation:

(F)=F/1+F^2

We move all terms to the left:

(F)-(F/1+F^2)=0


Domain of the equation: 1+F^2)!=0

We move all terms containing F to the left, all other terms to the right

F^2)!=-1

F!=-1/1

F!=-1

F∈R


We get rid of parentheses

-F^2-F/1+F=0

We multiply all the terms by the denominator


-F^2*1-F+F*1=0

We add all the numbers together, and all the variables

-F^2*1-1F+F*1=0

Wy multiply elements

-1F^2-1F+F=0

We add all the numbers together, and all the variables

-1F^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{0}{-2}=0$